| 14 March |
Largest Possible Volume for a Cylinder...? |
Pertinent Formulas:
Circumference of a Circle: 2r(pi)
Volume of a Cylinder: hr^2(pi)
h = 308/(Ï r) - r
dh/dr = -308/(Ï r²) - 1
V = Ï r² h
dV/dr = 2Ï r h + Ï r² dh/dr
= 2Ï r (308/(Ï r) - r) + Ï r² (-308/(Ï r²) - 1)
= 308 - 3Ï r²
dV²/dr² = -6Ï r
Find min/max by setting dV/dr = 0
3Ï r² = 308
r = 2√(77/(3Ï )) ............... dV²/dr² < 0, so it's a max
Answer: Max volume is (1232/3) √(77/(3Ï )) in² with r = 2√(77/(3Ï )) in and h = 4√(77/(3Ï )) in
Taylor, double check your calculations being mindful of the parentheses: 2√(77/(3Ï )) ≈ 5.72
77/(3Ï ) ≈ 8.17
√(8.17) ≈ 2.86
2 (2.86) = 5.72
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